Applied Statistics and Probability for Engineers, 6th Edition

Published by Wiley
ISBN 10: 1118539710
ISBN 13: 978-1-11853-971-2

Chapter 3 - Section 3-3 - Cumulative Distribution Functions - Exercises - Page 73: 3-56

Answer

$F(x)=\begin{aligned} &\left\{\begin{array}{ll}{0} & {x<217} \\ {0.005} & {217 \leq x<218} \\ {0.008} & {218 \leq x<231} \\ {0.053} & {231 \leq x<255} \\ {0.423} & {255 \leq x<267} \\ {0.574} & {267 \leq x<317} \\ {1} & {X\geq317} \end{array}\right.\end{aligned}$

Work Step by Step

Given, $f(x)=\left\{\begin{array}{ll}{0.005} & {x=217} \\ {0.003} & {x=218} \\ {0.045} & {x=231} \\ {0.370} & {x=255} \\ {0.151} & {x=267} \\ {0.426} & {x=317} \end{array}\right.$ then, $F(x)=\begin{aligned} &\left\{\begin{array}{ll}{0} & {x<217} \\ {f(217)=0.005} & {217 \leq x<218} \\ {0.005+f(218)=0.008} & {218 \leq x<231} \\ {0.008+f(231)=0.053} & {231 \leq x<255} \\ {0.053+f(255)=0.423} & {255 \leq x<267} \\ {0.423+f(267)=0.574} & {267 \leq x<317} \\ {0.574+f(317)=1} & {X\geq317} \end{array}\right.\end{aligned}$
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