Applied Statistics and Probability for Engineers, 6th Edition

Published by Wiley
ISBN 10: 1118539710
ISBN 13: 978-1-11853-971-2

Chapter 3 - Section 3-3 - Cumulative Distribution Functions - Exercises - Page 73: 3-38

Answer

$F(x)=\left\{\begin{array}{ll}{0,} & {x\lt0} \\{2/6,} & 0\leq x\lt1.5 \\ {4/6,} & {1.5\leq x\lt2} \\ {5/6,} & {2\leq x\lt3} \\ {1,} & {x\geq3} \end{array}\right.$

Work Step by Step

Given, $f(x)=\left\{\begin{array}{ll}{2/6,} & {x=0} \\ {2/6,} & {x=1.5} \\ {1/6,} & {x=2} \\ {1/6,} & {x=3} \end{array}\right.$ then, $F(x)=\left\{\begin{array}{ll}{0,} & {x\lt0} \\{2/6,} & 0\leq x\lt1.5 \\ {4/6,} & {1.5\leq x\lt2} \\ {5/6,} & {2\leq x\lt3} \\ {1,} & {x\geq3} \end{array}\right.$
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