Applied Statistics and Probability for Engineers, 6th Edition

Published by Wiley
ISBN 10: 1118539710
ISBN 13: 978-1-11853-971-2

Chapter 3 - Section 3-3 - Cumulative Distribution Functions - Exercises - Page 73: 3-53

Answer

$F(x)=\left\{\begin{array}{ll}{0,} & {X<266} \\ {48/200,} & {266 \leq X<271} \\ {108/200,} & {271 \leq X<274} \\ {1,} & {X \geq 274}\end{array}\right.$

Work Step by Step

Since, $f(x)=\left\{\begin{array}{ll} {48/200,} & {X=266} \\ {60/200,} & {X=271} \\ {92/200,} & {X = 274}\end{array}\right.$ then, $F(x)=\left\{\begin{array}{ll}{0,} & {X<266} \\ {48/200,} & {266 \leq X<271} \\ {48/200+60/200=108/200,} & {271 \leq X<274} \\ {1,} & {X \geq 274}\end{array}\right.$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.