Applied Statistics and Probability for Engineers, 6th Edition

Published by Wiley
ISBN 10: 1118539710
ISBN 13: 978-1-11853-971-2

Chapter 3 - Section 3-3 - Cumulative Distribution Functions - Exercises - Page 73: 3-45

Answer

$F(x)=\left\{\begin{array}{ll}{0} & {X<0} \\ {0.008} & {0 \leq X<1} \\ {0.104} & {1 \leq X<2} \\ {0.488} & {2 \leq X<3} \\ {1} & {X \geq 3}\end{array}\right.$

Work Step by Step

Since, $f(x)=\left\{\begin{array}{ll} {0.008} & { X=0} \\ {0.096} & {X=1} \\ {0.384} & {X=2 } \\ {0.512} & {X = 3}\end{array}\right.$ then, $F(x)=\left\{\begin{array}{ll}{0} & {X<0} \\ {0.008} & {0 \leq X<1} \\ {0.008+0.096=0.104} & {1 \leq X<2} \\ {0.104+0.384=0.488} & {2 \leq X<3} \\ {1} & {X \geq 3}\end{array}\right.$
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