Answer
$\mu=E(X)=2$
$\sigma^{2}=\frac{2}{3}$
Work Step by Step
$\mu=E(X)=\frac{b+a}{2}=\frac{3+1}{2}=2$
$\sigma^{2}=\frac{(b-a+1)^{2}-1}{12}=\frac{(3-1+1)^{2}-1}{12}=\frac{2}{3}$
Applied Statistics and Probability for Engineers, 6th Edition
by Montgomery, Douglas C.; Runger, George C.
Published by
Wiley
ISBN 10:
1118539710
ISBN 13:
978-1-11853-971-2
Chapter 3 - Section 3-5 - Discrete Uniform Distribution - Exercises - Page 79: 3-77
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