Chapter 3 - Section 3-5 - Discrete Uniform Distribution - Exercises - Page 79: 3-80

$\mu=E(X)=590.45 mm$ $\sigma^{2}=0.0825 mm^{2}$

Let $X=\frac{1}{10}y,y=5900,5901,...,5909$ $\mu=E(X)=\frac{1}{10}E(y)=(\frac{1}{10}).\frac{5909+5900}{2}=590.45$ $\sigma^{2}=(\frac{1}{10})^{2}.V(y)=(\frac{1}{10})^{2}.\frac{(5909-5900+1)^{2}-1}{12}=0.0825$