Answer
$20$
Work Step by Step
$S=\displaystyle \sum(x-5)^{2}$ = sum of all the squares of differences.
\begin{align*}
S&=(3-5)^{2}+(8-5)^{2}+(4-5)^{2}+(5-5)^{2}\\&\,\,+(3-5)^{2}+(4-5)^{2}+(6-5)^{2}\\
&=4+9+1+0+4+1+1\\
&=20\end{align*}
Statistics (12th Edition)
by McClave, James T.; Sincich, Terry T.
Published by
Pearson
ISBN 10:
0321755936
ISBN 13:
978-0-32175-593-3
Chapter 2 - Methods for Describing Sets of Data - Exercises 2.44 - 2.47 - Learning the Mechanics - Page 50: 2.45c
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