Answer
$71$
Work Step by Step
$S=\displaystyle \sum(x-2)^{2}$ = sum of all the squares of differences.
\begin{align*}
S&=(3-2)^{2}+(8-2)^{2}+(4-2)^{2}+(5-2)^{2}+(3-2)^{2}+(4-2)^{2}+(6-2)^{2}\\\\
&=1+36+4+9+1+4+16\\
&=71\end{align*}
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