Statistics for the Life Sciences (5th Edition)

Published by Pearson
ISBN 10: 0-32198-958-9
ISBN 13: 978-0-32198-958-1

Chapter 2 - Description of Sample and Populations - Exercises 2.3.1 - 2.3.14 - Page 44: 2.3.2

Answer

Sample: 7, 11, 15, 25, 42

Work Step by Step

$x ̅=\frac{7+11+15+25+42}{5}=\frac{100}{5}=20$ Position of the median: $0.5(n+1)=0.5(5+1)=3$ That is, for a sample of size 5, the median is the value of the third observation. In the given sample it is the 15.
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