Answer
Mean:
$y ̅ =3.389~lb/day$
Median:
$y ̃=3.335~lb/day$
Work Step by Step
The new sample: 2.46 3.89 3.51 3.97 3.31 3.21 3.36 3.67 3.24 3.27
$y ̅ =\frac{∑y_i}{n}=\frac{2.46+3.89+3.51+3.97+3.31+3.21+3.36+3.67+3.24+3.27}{10}=\frac{33.89}{10}=3.389$
The sample in ascending order:
2.46 3.21, 3.24, 3.27, 3.31, 3.36, 3.51, 3.67, 3.89, 3.97
Position of the median:
$0.5(n+1)=0.5(10+1)=5.5$
That is, for a sample of size 10, the median is the mean between the values of the fifth and the sixth observations in ascending order. In the given sample it is $\frac{3.31+3.36}{2}=3.335$.
