Answer
Mean:
$y ̅ =3.492~lb/day$
Median:
$y ̃=3.36~lb/day$
Work Step by Step
$y ̅ =\frac{∑y_i}{n}=\frac{3.89+3.51+3.97+3.31+3.21+3.36+3.67+3.24+3.27}{9}=\frac{31.43}{9}=3.492$
The sample in ascending order:
3.21, 3.24, 3.27, 3.31, 3.36, 3.51, 3.67, 3.89, 3.97
Position of the median:
$0.5(n+1)=0.5(9+1)=5$
That is, for a sample of size 9, the median is the value of the fifth observation in ascending order. In the given sample it is 3.36.
