Answer
$F_0\lt F_{\frac{α}{2},n_1-1,n_2-1}$: null hypothesis is not rejected.
There is not enough evidence to conclude that $σ_1\gtσ_2$
Work Step by Step
$F_0=\frac{s_1^2}{s_2^2}=\frac{9.9^2}{6.4^2}=2.39$
$d.f_1=n_1-1=26-1=25$
$d.f_2=n_2-1=19-1=18$
Right-tailed test:
$F_{\frac{α}{2},n_1-1,n_2-1}=F_{0.01,25,18}=2.84$
(According to table VIII, for $d.f._1=25$, $d.f._2=20$, the closest value to 18, and area in the right tail = 0.05)
Since $F_0\lt F_{\frac{α}{2},n_1-1,n_2-1}$, we do not reject the null hypothesis.
