Answer
$F_{1-\frac{α}{2},n_1-1,n_2-1}\lt F_0\lt F_{\frac{α}{2},n_1-1,n_2-1}$: null hypothesis is not rejected.
There is not enough evidence to conclude that $σ_1\neσ_2$.
Work Step by Step
$F_0=\frac{s_1^2}{s_2^2}=\frac{3.2^2}{3.5^2}=0.84$
$d.f_1=n_1-1=16-1=15$
$d.f_2=n_2-1=16-1=15$
Two-tailed test:
$F_{\frac{α}{2},n_1-1,n_2-1}=F_{0.025,15,15}=2.86$
(According to table VIII, for $d.f._1=15$, $d.f._2=15$ and area in the right tail = 0.025)
$F_{1-\frac{α}{2},n_1-1,n_2-1}=F_{0.975,15,15}=\frac{1}{F_{0.025,15,15}}=\frac{1}{2.86}=0.35$
Since $F_{1-\frac{α}{2},n_1-1,n_2-1}\lt F_0\lt F_{\frac{α}{2},n_1-1,n_2-1}$, we do not reject the null hypothesis.
