Answer
$F_0\lt F_{1-α,n_1-1,n_2-1}$: null hypothesis is rejected.
There is enough evidence to conclude that $σ_1\ltσ_2$
Work Step by Step
$H_0:~σ_1=σ_2$ versus $H_1:σ_1\ltσ_2$
$F_0=\frac{s_1^2}{s_2^2}=\frac{8.3^2}{13.2^2}=0.40$
$d.f_1=n_1-1=51-1=50$
$d.f_2=n_2-1=26-1=25$
Left-tailed test:
$F_{α,n_1-1,n_2-1}=F_{0.1,50,25}=1.61$
(According to table VIII, for $d.f._1=50$, $d.f._2=25$ and area in the right tail = 0.1)
$F_{1-α,n_1-1,n_2-1}=F_{0.9,50,25}=\frac{1}{F_{0.1,50,25}}=\frac{1}{1.61}=0.62$
Since $F_0\lt F_{1-α,n_1-1,n_2-1}$, we reject the null hypothesis.
