Trigonometry (10th Edition)

Published by Pearson
ISBN 10: 0321671775
ISBN 13: 978-0-32167-177-6

Chapter 1 - Trigonometric Functions - Section 1.4 Using the Definitions of the Trigonometric Functions - 1.4 Exercises - Page 36: 9

Answer

$\frac{\sqrt 2}{2}$

Work Step by Step

1.Reciprocal identity $\sin\theta=\frac{1}{\csc\theta}$ 2. Substitute the given value: $\sin\theta=\frac{1}{\frac{\sqrt 8}{2}}=\frac{2}{\sqrt 8}=\frac{\sqrt 8}{4}=\frac{\sqrt 2}{2}$
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