Trigonometry 7th Edition

Published by Cengage Learning
ISBN 10: 1111826854
ISBN 13: 978-1-11182-685-7

Chapter 1 - Section 1.1 - Angles, Degrees, and Special Triangles - 1.1 Problem Set - Page 13: 59

Answer

Longest side = $ \frac{4\sqrt 2}{5} \approx 1.13$

Work Step by Step

In a 45°–45°–90° triangle, if each of the shorter side is 'x'. then as per Pythagorean theorem- $longest side^{2}$ = $x^{2} + x^{2}$ = 2$x^{2}$ Therefore longest side = $x\sqrt 2$ Given that each of the shorter sides is $ \frac{4}{5}$ Hence longest side = $ \frac{4}{5} \times \sqrt 2$ = $ \frac{4\sqrt 2}{5} $ $Longest side \approx \frac{4}{5} \times 1.414$ $Longest side \approx 1.13$
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