Answer
$\cos{\theta} =0.8
\\\sin{\theta} =0.6$
Work Step by Step
(Assumption: the angle is in standard position)
If the point $(9.36, 7.02)$ is on the terminal side of $\theta$. then $r$ can be solved using the formula:
$r=\sqrt{x^2 + y^2}$
The given point has $x=9.36$ and $y=7.02$. Substitute these values into the formula above to obtain:
$r= \sqrt{9.36^2 + 7.02^2}
\\r = 11.7$
RECALL:
$\sin{\theta} = \dfrac{y}{r}
\\\cos{\theta} = \dfrac{x}{r}$
Use the formulas above and the known values of x, y, and r to obtain:
$\cos{\theta} = \dfrac{936}{11.7}=0.8
\\\sin{\theta} = \dfrac{7.02}{11.7}=0.6$
