Answer
True
Work Step by Step
As can be seen from the figure:
$$\sec{60^\circ} = \dfrac{r_1}{x}\,\,\, \&\,\,\,\, \sec{75^\circ} = \dfrac{r_2}{x}$$
$$r_1 = \sqrt{x^2+y_1^2} \,\,\,\,\,\&\,\,\,\,\,r_2 = \sqrt{x^2+y_2^2}$$
$$\because y_2 > y_1 \,\,\,\,\,\, \therefore r_2 > r_1$$
$\therefore \sec(75^{\circ}) > \sec(60^{\circ})$
