Answer
False
Work Step by Step
As can be seen from the figure:
$$\cot{60^\circ} = \dfrac{x}{y_1}\,\,\, \&\,\,\,\, \cot{75^\circ} = \dfrac{x}{y_2}$$
$$\because y_2 > y_1 $$
$$\therefore \cot(60^{\circ}) > \cot(75^{\circ})$$
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