Trigonometry 7th Edition

Published by Cengage Learning
ISBN 10: 1111826854
ISBN 13: 978-1-11182-685-7

Chapter 1 - Section 1.5 - More on Identities - 1.5 Problem Set - Page 45: 21

Answer

$\tan^{2}\theta$

Work Step by Step

Given expression is- $\frac{\tan\theta}{\cot\theta}$ = $\frac{\sin\theta/\cos\theta}{\cos\theta/\sin\theta}$ = $ \frac{\sin\theta}{\cos\theta} \times \frac{\sin\theta}{\cos\theta}$ = $\frac{\sin^{2}\theta}{\cos^{2}\theta}$ = $\tan^{2}\theta$ Alternate Method- $\frac{\tan\theta}{\cot\theta}$ = $\tan\theta\times\frac{1}{\cot\theta}$ = $\tan\theta\times\tan\theta$ = $\tan^{2}\theta$
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