Trigonometry 7th Edition

Published by Cengage Learning
ISBN 10: 1111826854
ISBN 13: 978-1-11182-685-7

Chapter 1 - Section 1.5 - More on Identities - 1.5 Problem Set - Page 45: 22

Answer

$\cot^{2}\theta$

Work Step by Step

Given expression is- $\frac{\cot\theta}{\tan\theta}$ = $\frac{\cos\theta/\sin\theta}{\sin\theta/\cos\theta}$ = $ \frac{\cos\theta}{\sin\theta} \times \frac{\cos\theta}{\sin\theta}$ = $\frac{\cos^{2}\theta}{\sin^{2}\theta}$ = $\cot^{2}\theta$ Alternate Method- $\frac{\cot\theta}{\tan\theta}$ = $\cot\theta\times\frac{1}{\tan\theta}$ = $\cot\theta\times\cot\theta$ = $\cot^{2}\theta$
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