Trigonometry 7th Edition

Published by Cengage Learning
ISBN 10: 1111826854
ISBN 13: 978-1-11182-685-7

Chapter 1 - Section 1.5 - More on Identities - 1.5 Problem Set - Page 45: 29

Answer

$ \cos\theta$

Work Step by Step

Given expression is- $\sec\theta - \tan\theta\sin\theta$ = $\frac{1}{\cos\theta} - \frac{\sin\theta}{\cos\theta}\times\sin\theta$ = $\frac{1}{\cos\theta} - \frac{\sin^{2}\theta}{\cos\theta}$ =$ \frac{1 - \sin^{2}\theta}{\cos\theta} $ = $\frac{\cos^{2}\theta}{\cos\theta}$ ( From first Pythagorean identity, $ (1 - \sin^{2}\theta)$ can be written as $\cos^{2}\theta$) = $ \cos\theta$
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