Answer
$ \sin^{2}\theta +7\sin\theta +12$
Work Step by Step
Given expression is-
$ (\sin\theta+4) (\sin\theta+3)$
= $ \sin^{2}\theta +3\sin\theta +4\sin\theta +12$
( By FOIL method)
= $ \sin^{2}\theta +7\sin\theta +12$
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