Answer
Q II
Work Step by Step
Given-
$\csc\theta\gt 0$
i.e $\csc\theta$ is positive.
Also given $\cos\theta\lt 0$ i.e. $\cos\theta$ is negative
Therefore $\theta$ terminates in QII, as $\csc\theta$ is positive and $\cos\theta$ is negative.
Trigonometry 7th Edition
by McKeague, Charles P.; Turner, Mark D.
Published by
Cengage Learning
ISBN 10:
1111826854
ISBN 13:
978-1-11182-685-7
Chapter 1 - Test - Page 51: 17
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