Answer
See below.
Work Step by Step
Using what we learned: $\sin135^\circ=\frac{1}{\sqrt2},\cos135^\circ=-\frac{1}{\sqrt2},\frac{\sin135^\circ}{\cos135^\circ}=\frac{\frac{1}{\sqrt2}}{-\frac{1}{\sqrt2}}=-1$, which is undefined.
Trigonometry 7th Edition
by McKeague, Charles P.; Turner, Mark D.
Published by
Cengage Learning
ISBN 10:
1111826854
ISBN 13:
978-1-11182-685-7
Chapter 2 - Section 2.2 - Calculators and Trigonometric Functions of an Acute Angle - 2.2 Problem Set - Page 73: 92
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