Answer
$PbO$
Work Step by Step
We can denote the molecular formula of the lead oxide by $Pb_{x}O_{y}$. Knowing it is 92.83% lead, we can obtain the following equation:
$\omega (Pb) = 0.9283 = \frac{x \times Ar(Pb)}{Mr(Pb_{x}O_{y})}=\frac{x\times 207}{x\times 207 + y \times 16}$
$\implies 16\times x = 16\times y \implies x = y$
The simplest formula of this oxide is therefore $PbO$ (that is when $x = y = 1$).
