Answer
a) $\rho (NaHCO_{3})=2.16\frac{g}{ml}$
b) $\rho (I_{2})=4.93\frac{g}{ml}$
c) $\rho (Hg)=13.62\frac{g}{ml}$
d) $\rho (NaCl)=2.17\frac{g}{ml}$
Work Step by Step
Density of a compound can be calculated by dividing its molecular weight by molecular volume:
a) $\rho (NaHCO_{3})=\frac{84\frac{g}{mol}}{0.0389\frac{l}{mol}}=2159.4\frac{g}{l}\approx 2.16\frac{g}{ml}$
b) $\rho (I_{2})=\frac{254\frac{g}{mol}}{0.05148\frac{l}{mol}}=4933.95\frac{g}{l}\approx 4.93\frac{g}{ml}$
c) $\rho (Hg)=\frac{201\frac{g}{mol}}{0.01476\frac{l}{mol}}=13617.9\frac{g}{l}\approx 13.62\frac{g}{ml}$
d) $\rho (NaCl)=\frac{58.5\frac{g}{mol}}{0.02699\frac{l}{mol}}=2167.5\frac{g}{l}\approx 2.17\frac{g}{ml}$
