Chemistry 10th Edition

Published by Brooks/Cole Publishing Co.
ISBN 10: 1133610668
ISBN 13: 978-1-13361-066-3

Chapter 2 - Chemical Formulas and Composition Stoichiometrhy - Exercises - Building Your Knowledge - Page 79: 115

Answer

$1.67\times10^{21}\, molecules$

Work Step by Step

Volume of water= $0.050\, mL=0.050\,cm^{3}$ Mass of water= $\text{Density}\times \text{Volume}$ $=(1.00\, g/cm^{3})(0.050\, cm^{3}) $ $=0.050\, g$ $\text{Number of moles}=\frac{\text{Mass in grams}}{\text{Molar mass}}$ $=\frac{0.050\,g}{18.0\,g/mol}=0.00277778\,mol$ Number of molecules= $(0.00277778\,mol)(6.022\times10^{23}/mol)$ $=1.67\times10^{21}\, molecules$
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