Answer
This is a basic solution.
Work Step by Step
1. Calculate the hydronium ion concentration:
$[OH^-] * [H_3O^+] = Kw = 10^{-14}$
$ 8.0 \times 10^{- 3} * [H_3O^+] = 10^{-14}$
$[H_3O^+] = \frac{10^{-14}}{ 8.0 \times 10^{- 3}}$
$[H_3O^+] = 1.2 \times 10^{- 12}M$
2. Identify which one is greater: $[H_3O^+]$ or $[OH^-]$
- Since $8.0 \times 10^{-3} \gt 1.2 \times 10^{-12}$, the hydroxide ion concentration is greater. Which means that this is a basic solution.
$[H_3O^+] \lt [OH^-]:$ Basic solution.
