Answer
This is an acidic solution.
Work Step by Step
1. Calculate the hydronium ion concentration:
$[OH^-] * [H_3O^+] = Kw = 10^{-14}$
$ 3.5 \times 10^{- 10} * [H_3O^+] = 10^{-14}$
$[H_3O^+] = \frac{10^{-14}}{ 3.5 \times 10^{- 10}}$
$[H_3O^+] = 2.9 \times 10^{- 5}M$
2. Identify which one is greater: $[H_3O^+]$ or $[OH^-]$
- Since $2.9 \times 10^{-5} \gt 3.5 \times 10^{-10}$, the hydronium ion concentration is greater. Which means that this is an acidic solution.
$[H_3O^+] \gt [OH^-]:$ Acidic solution.
