Answer
This is an acidic solution.
Work Step by Step
1. Calculate the hydroxide ion concentration:
$[OH^-] * [H_3O^+] = Kw = 10^{-14}$
$ 5.0 \times 10^{- 12} * [H_3O^+] = 10^{-14}$
$[H_3O^+] = \frac{10^{-14}}{ 5.0 \times 10^{- 12}}$
$[H_3O^+] = 2.0 \times 10^{- 3}M$
2. Identify which one is greater: $[H_3O^+]$ or $[OH^-]$
- Since $2.0 \times 10^{-3} \gt 5.0 \times 10^{-12}$, the hydronium ion concentration is greater. Which means that this is an acidic solution.
$[H_3O^+] \gt [OH^-]:$ Acidic solution.
