College Physics (7th Edition)

Published by Pearson
ISBN 10: 0-32160-183-1
ISBN 13: 978-0-32160-183-4

Chapter 1 - Measurement and Problem Solving - Learning Path Questions and Exercises - Exercises - Page 28: 3

Answer

$\textbf{(a)}$ $40000000\, \text{bytes} = 40\,\mathrm{MB}$ $\textbf{(b)}$ $0.5722\, \text{mL} = 0.5722\times10^{-3}\,\mathrm{L}$ $\textbf{(c)}$ $2.684\, \text{m} = 268.4\,\mathrm{cm}$ $\textbf{(d)}$ $5500\, \text{bucks} = 5.5\,\mathrm{kilo bucks}$

Work Step by Step

$\textbf{(a)}$ As we know $1 \,\mathrm{M} = 1000000 = 10^6$, so, divide the given number by $1000000$ or $10^6$, we get $40000000\, \text{bytes} = 40\,\mathrm{MB}$ $\textbf{(b)}$ As we know $1 \,\mathrm{mili} = \frac{1}{1000} = 10^{-3}$, so, multiply the given number by $1 \,\mathrm{mili} = \frac{1}{1000} = 10^{-3}$, we get $0.5722\, \text{mL} = 0.5722\times10^{-3}\,\mathrm{L}$ $\textbf{(c)}$ As we know $1 \,\mathrm{centi} = \frac{1}{100} = 10^{-2}$, so, multiply the given number by $100 = 10^{2}$, we get $2.684\, \text{m} = 2.684\times10^{2}\,\mathrm{cm} = 268.4\,\mathrm{cm}$ $\textbf{(d)}$ As we know $1 \,\mathrm{kilo} = 1000 = 10^{3}$, so, divide the given number by $1000 = 10^{3}$, we get $5500\, \text{bucks} = \frac{5500}{1000}\,\mathrm{kilo bucks} = 5.5\,\mathrm{kilo bucks}$
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