Answer
The given equation is dimensionally correct.
Work Step by Step
$x = x_0 + vt$
Here $x$ has unit of length, hence dimentional formula for $x$ is $\text{L}^1$
Similarly $x_0$ has unit of length, hence dimentional formula for $x_0$ is $\text{L}^1$
$t$ has unit of time, hence dimentional formula for $t$ is $\text{T}^1$
The unit of $v$ is $ms^{-1}$ , hence dimentional formula for $v$ is $\text{L}^1\text{T}^{-1}$.
Hence from the given equation
$\text{L}^1 = \text{L}^1 + \text{L}^1\text{T}^{-1}\text{T}^1$
OR
$\text{L}^1 = \text{L}^1 + \text{L}^1$
The given equation is dimensionally correct.
