Answer
$a). 6 m/s$
$b). 18 m/s$
Work Step by Step
$x=3\times t^{2}$
a). average velocity for $\Delta t = 2.0 s - 0 s$ = $\frac{3\times 2^{2}-0}{2.0 - 0 }=6 m/s$
b). average velocity for $\Delta t = 4.0 s - 2.0 s$ = $\frac{3\times 2^{4}-3\times2^{2}}{4.0 - 2.0 }=\frac{48-12}{2}=18 m/s$