College Physics (7th Edition)

Published by Pearson
ISBN 10: 0-32160-183-1
ISBN 13: 978-0-32160-183-4

Chapter 2 - Kinematics: Description of Motion - Learning Path Questions and Exercises - Exercises - Page 61: 31

Answer

$a). 26.35 m/s$ $b). 11.08 s$

Work Step by Step

a). $u=35km/hr = 35 \times \frac{1000}{3600} m/s=9.722 m/s$ $a=1.5m/s^{2}$ $S=200m$ So, $v^{2}=u^{2}+2aS=9.722^{2}+2\times 1.5\times 200$ $v=26.35\,m/s$ b). $v=u+at$ $t=\frac{v-u}{a}=\frac{26.35-9.722}{1.5}=11.08s$
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