College Physics (7th Edition)

Published by Pearson
ISBN 10: 0-32160-183-1
ISBN 13: 978-0-32160-183-4

Chapter 2 - Kinematics: Description of Motion - Learning Path Questions and Exercises - Exercises - Page 61: 25

Answer

$3.725s$

Work Step by Step

$60mi/hr = 26.82 m/s$ time taken to accelerate to 26.82 m/s = $\frac{26.82 m/s}{7.2 m/s^{2}}=3.725s$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.