College Physics (7th Edition)

Published by Pearson
ISBN 10: 0-32160-183-1
ISBN 13: 978-0-32160-183-4

Chapter 2 - Kinematics: Description of Motion - Learning Path Questions and Exercises - Exercises - Page 63: 47

Answer

$a=2.18\times10^{5} m/s^{2}$

Work Step by Step

u=330 m/s, S=0.25 m. v=0. $v^{2}=u^{2}+2aS$ $0=330^{2}-2\times a\times 0.25$ $a=\frac{330^{2}}{0.5}=2.18\times10^{5} m/s^{2}$
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