Answer
a). Required $t=31.74s$
b). Their travel distance difference$=85.71m$
c). Their displacements are equal, their is no difference, since their initial and final positions are same.
d). $\frac{v_{A}}{v_{B}}=\frac{11}{7}$
Work Step by Step
a). Required $t=\frac{\frac{22}{7}\times r-2r}{v}=\frac{8}{7}\times \frac{75}{2.7}=31.74s$
b). Their travel distance difference$=\frac{22}{7}\times r-2r=85.71m$
c). Their displacements are equal, their is no difference, since their initial and final positions are same.
d). Since speed is same for both joggers,
$\frac{2r}{t_{A}}=\frac{\frac{22}{7}\times r}{t_{B}}$
$\frac{t_{B}}{t_{A}}=\frac{11}{7}$
Thus, $\frac{v_{A}}{v_{B}}=\frac{\frac{D}{t_{A}}}{\frac{D}{t_{B}}}=\frac{11}{7}$
