College Physics (7th Edition)

Published by Pearson
ISBN 10: 0-32160-183-1
ISBN 13: 978-0-32160-183-4

Chapter 2 - Kinematics: Description of Motion - Learning Path Questions and Exercises - Exercises - Page 65: 79

Answer

$a). 38.73m/s$ $b). 15.492s$ $c). 19.14m/s$

Work Step by Step

a). $v^{2}=u^{2}+2aS$ $0=u^{2}-2\times 2.5\times 300$ $u=38.73m/s$ b). $t=\frac{v-u}{a}=\frac{0-(38.73)}{-2.5}=15.492s$ c). For the other vehicle, $u=38.73+4.47=43.2m/s$ $v^{2}=43.2^{2}-2\times 2.5\times300$ $v=19.14m/s$
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