Answer
We can rank the graphs according to the specific heats of the objects:
$c \gt b \gt a$
Work Step by Step
We can find an expression for the specific heat in each case:
$Q = cm~\Delta T$
$c = \frac{Q}{m~\Delta T}$
Note that the mass $m$ is equal in all three cases.
If the temperature of the water increases more and more, then the value of $Q$ is greater.
In graph a, $\Delta T$ is the largest and $Q$ is the smallest. Thus the specific heat of a is the smallest.
In graph c, $\Delta T$ is the smallest and $Q$ is the greatest. Thus the specific heat of c is the greatest.
We can rank the graphs according to the specific heats of the objects:
$c \gt b \gt a$
