Answer
Q-W = 0
Q=W
Here, We can see all heat Q is converted into workdone,
Work Step by Step
Hence both cycle are transvered clockwise, Then the total energy transformed by the gas as heat Q will be positive.
Q=W the net work work done of cycle 2 is greater than the cycle 1, Then we can conclude that heat Q2 of cycle 2 is also greater than the net energy transformed by the gas as heat Q1 of cycle 1.
