Answer
W is greater in Cycle 2.
Work Step by Step
We can write an expression for the work done by a gas:
$W = \int_{V_i}^{V_f}~p~dV$
Note that if the volume does not change, then the work done by the gas is zero. Thus the work done by a gas along each vertical section is zero.
For the net work to be positive, we should move around the diagram so that the section at higher pressure moves from a lower volume to a higher volume.
If the cycle is traversed clockwise, then the net work $W$ done by the gas is equal to the area enclosed by the cycle.
Since the area enclosed by the cycle in Cycle 2 is greater, then W is greater in Cycle 2.
