Physics: Principles with Applications (7th Edition)

Published by Pearson
ISBN 10: 0-32162-592-7
ISBN 13: 978-0-32162-592-2

Chapter 2 - Describing Motion: Kinematics in One Dimension - Problems - Page 44: 20

Answer

8.44s

Work Step by Step

First, we convert 65 km/h to 18.1 m/s and 120 km/h to 33.3 m/s. Next, we use the equation below to find t: v = $v_{0}$ + at t = $\frac{v-v_{0}}{a}$ t = $\frac{33.3m/s - 18.1m/s}{1.8m/s^2}$ t = 8.44s
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