Answer
(a) 8.81 seconds
(b) 86.3 m/s
Work Step by Step
(a) $y = \frac{1}{2}at^2$
$t^2 = \frac{2y}{a} = \frac{2\times380}{9.80} = 77.55$
$t = \sqrt{77.55} = 8.81 ~s$
(b) $v = v_0 + at = 0 + 9.80\times8.81 = 86.3 ~m/s$
Physics: Principles with Applications (7th Edition)
by Giancoli, Douglas C.
Published by
Pearson
ISBN 10:
0-32162-592-7
ISBN 13:
978-0-32162-592-2
Chapter 2 - Describing Motion: Kinematics in One Dimension - Problems - Page 44: 40
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