Answer
a) 1.2 $m/s^2$
b) 106 m
Work Step by Step
a) We solve using the equation:
v = $v_{o}$ + at
a = $\frac{v-v_{o}}{t}$
a = $\frac{21m/s - 14m/s}{6.0s}$
a = 1.2 $m/s^2$
b) We solve using the equation:
x = $v_{o}t + \frac{1}{2}at^2$
x = $(14m/s)(6.0s) + \frac{1}{2}(1.2m/s^2)(6.0s)^2$
x = 106m
