Answer
23 m/s
Work Step by Step
$v_{o}$ = $\sqrt{v^{2} - 2a(x-x_{0})}$
$v_{o}$ = $\sqrt{0^{2} - 2(-4m/s^2)(65m)}$
$v_{o}$ $\approx$ $23m/s$
Physics: Principles with Applications (7th Edition)
by Giancoli, Douglas C.
Published by
Pearson
ISBN 10:
0-32162-592-7
ISBN 13:
978-0-32162-592-2
Chapter 2 - Describing Motion: Kinematics in One Dimension - Problems - Page 44: 28
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