Answer
$−2.248\text{ kJ/kg}$
$−2.234\text{ kJ/kg}$
Work Step by Step
Using the definition of Gibbs function and enthalpy and entropy data from Table A-11, $$
\begin{aligned}
& g_f=h_f-T s_f=(38.53 \mathrm{~kJ} / \mathrm{kg})-(263.15 \mathrm{~K})(0.15496 \mathrm{~kJ} / \mathrm{kg} \cdot \mathrm{K})=-2.248 \mathrm{~kJ} / \mathrm{kg} \\
& g_g=h_g-T s_g=(244.55 \mathrm{~kJ} / \mathrm{kg})-(263.15 \mathrm{~K})(0.93782 \mathrm{~kJ} / \mathrm{kg} \cdot \mathrm{K})=-2.234 \mathrm{~kJ} / \mathrm{kg}
\end{aligned}
$$ which are sufficiently close. Therefore, the criterion for phase equilibrium is satisfied.
