Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter R - Section R.1 - Factors and the Least Common Multiple - Exercise Set - Page R-6: 1

Answer

Factors: $1$, $3$, $9$

Work Step by Step

Start with the number $1$. Divide $9$ by $1$. The result is $9$. $9=1\cdot 9$ $1$ and $9$ are factors of $9$. Since $9$ is not a prime number, we can check for additional factors. Divide $9$ by $2$. The result is $4.5$ (not a whole number). $2$ does not divide evenly into $9$. Divide $9$ by $3$. The result is $3$. $3$ is another factor of $9$. $9=3\cdot 3$ Since $9$ is not divisible by any number greater than $3$, we have found all the factors.
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