Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter R - Section R.1 - Factors and the Least Common Multiple - Exercise Set - Page R-6: 3

Answer

Factors: $1, 2, 3, 4, 6, 8, 12$ and $24$

Work Step by Step

Start with the number $1$. Divide $24$ by $1$. The result is $24$. $24=1\cdot 24$ $1$ and $24$ are factors of $24$. Divide $24$ by $2$. The result is $12$. $2$ and $12$ are additional factors of $24$. $24=2\cdot 12$ Divide $24$ by $3$. The result is $8$. $3$ and $8$ are additional factors of $24$. $24=3\cdot 8$ Divide $24$ by $4$. The result is $6$. $4$ and $6$ are more factors of $24$. $24=4\cdot 6$ Finally, divide $24$ by $6$, which equals $4$. Thus the factors of $24$ are $1, 2, 3, 4, 6, 8, 12$ and $24$.
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