Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter R - Section R.1 - Factors and the Least Common Multiple - Exercise Set - Page R-6: 4

Answer

Factors: $1, 2, 3, 4, 6, 9, 12, 18$ and $36$

Work Step by Step

Begin with the number $1$. Divide $36$ by $1$. The result is $36$. $36=1\cdot 36$ $1$ and $36$ are factors of $36$. Divide $36$ by $2$. The result is $18$. $36=2\cdot 18$ $2$ and $18$ are additional factors of $36$. Divide $36$ by $3$. The result is $12$. $36=3\cdot 12$. $3$ and $12$ are more factors of $36$. Divide $36$ by $4$. The result is $9$. $36=4\cdot 9$ $4$ and $9$ are additional factors of $36$. Divide $36$ by $6$. The result is $6$. $36=6\cdot 6$ $6$ is another factor of $36$. Finally, divide $36$ by $9$, which equals $4$. Thus, the factors of $36$ are $1, 2, 3, 4, 6, 9, 12, 18$ and $36$.
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